The phenomenon of bending of light and spreading into geometrical shadow after passing through obstacle or slits is called diffraction.
The diffraction pattern can be obtained on the screen when
width of slit is equivalent to wavelength of light. The bright and the dark
fringes obtained on the screen due to diffraction are called secondary maxima
and minima.
Types of diffraction:
On the basis of arrangement of device used, there are two types
of diffraction. They are:
1.Fresnel’s diffraction:
The diffraction which is obtained due to the source slits
and screen at a finite distance is called fresnel’s diffraction. In this
diffraction, the wave front is spherical. So, diffraction pattern obtained on
the screen are quite complex.
2.Fraunhoffer’s diffraction:
The diffraction which is obtained due to the source slits
and screen at infinite distance is called fraunhoffer’s diffraction. In this
diffraction, the wave front is plane. So, diffraction pattern obtained on the
screen are simple. In this diffraction lenses are used to converge the ray of
light on screen or slits.
Fraunhoffers’s single slits diffraction:
Figure shows experimental arrangement of fraunhoffers single
slits diffraction. It consists of two lenses ‘L1, and ‘L2’ for the converging
of ray of light on slit and screen from the source ‘S’.
All parallel rays of light focus at the center of screen.
So, center of screen is bright called center maxima.
On the screen, diffraction pattern i.e., bright and dark
fringes is obtained due to superimpose of diffracted rays which are called
secondary maxima and minima.
Draw ‘AN’ perpendicular on ‘BP’ the ‘BN’ gives path
difference between ‘AP’ and ‘BP’ rays.
Therefore, path difference(x)=BN
In triangle ABN,
\(\sin\theta=\frac{BN}{AB}=\frac{BN}{a}\)
Where a=width of slits
BN=asinθ
Therefore, path difference(x)=asinθ….(i)
For secondary maxima,
Path difference(x)=$\frac{(2n+1)\lambda}{2}$
Where n=0,1,2
$a\sin\theta=\frac{(2n+1)\lambda}{2}$
$\sin\theta=\frac{(2n+1)\lambda}{2a}$
For small θ, $sinθ\approxθ$
$\therefore \theta_n=\frac{(2n+1)\lambda}{2a}$
This is the angular width of nth
secondary maxima.
For n=1, $\theta_1=\frac{3\lambda}{2a}$ 1st secondary maxima
For n=2, $\theta_2=\frac{5\lambda}{2a}$ 2nd secondary maxima
If ‘y’ be linear width of nth fringe and
‘D’ be distance between slit and screen. Then,
$\theta=\frac{y_n}{D}$
$y_n=θnD$
$y_n=\frac{(2n+1)\lambda\,D}{2a}$
For secondary minima,
Path difference(x)=$n\lambda$
$a\sin\theta=n\lambda$
$\sin\theta=\frac{n\lambda}{a}$
for small θ, ${\sin\theta}\approx\theta$
$\theta=\frac{n\lambda}{a}$
Angular width of nth secondary minima
and,
$y_n={\theta_n}\,{D}$
$y_n=\frac{n\lambda\,D}{a}$ linear width of nth secondary minima
Width of central maxima:
The width of central maxima is twice
of 1st secondary minima
Width of central maxima=$2y=\frac{2\lambda\,D}{a}$
Angular width of central maxima=$2\,\theta_1=\frac{2\lambda}{a}$
Diffraction grating:
An arrangement of large number of
parallel slits is called diffraction grating. The diffraction grating can be
obtained by ruling lines over the glass surface.
When the lines are ruling over
transparent glass surface then the grating is called transmission grating.
And, when lines are ruling over
reflecting glass surface then the grating is called reflecting grating.
Let us consider N identical slits
of width ‘a’ separated by identical opaque of width ‘b’ in l inch glass then,
Na+Nb = 1 inch
N(a+b) = 1
a+b=$\frac{1}{N}$
Here, (a+b) is called grating
element. Hence, grating element is defined as the sum of width of each slit and
each opaque.
Path difference between rays is;
x=(a+b)sinθ
for maxima,
(a+b)sinθ=n$\lambda$
Dsinθ=n$\lambda$ where d=a+b
Resolving Power:
The ability of an
optical instrument to produce separate images of two objects very close to each
other is called is called resolving power.
Rayleigh Criterion:
When the central
maximum in the diffraction pattern of one point source falls over the first
minimum in the diffraction pattern of the other point source, then the
two-point sources are said to have been resolved by optical instrument.
Resolving power of a Microscope:
The
resolving power of a microscope is defined as the reciprocal of the distance
between two objects which can be just resolved when seen through microscope.
Resolving power=$\frac{1}{\Delta\,d}=\frac{2\mu\sin\theta}{\lambda}$
Resolving power depends on;
i.
Wavelength
ii.
Refractive index of the medium between
the object and the objective, and
iii. Half angle of the cone of light from one
of the objects .
Resolving power of telescope:
The resolving power of a telescope is
defined as the reciprocal of the smallest angular separation between two
distinct objects whose images are seen separately.
Resolving power=$\frac{1}{d\theta}=\frac{a}{1.22\lambda}$
Resolving power depends on;
i.
Wavelength
ii. Diameter of the objective