The phenomenon of bending of light and spreading into geometrical shadow after passing through obstacle or slits is called diffraction.
The diffraction pattern can be obtained on the screen when width of slit is equivalent to wavelength of light. The bright and the dark fringes obtained on the screen due to diffraction are called secondary maxima and minima.
Types of
diffraction:
On the basis
of arrangement of device used, there are two types of diffraction. They are:
1. Fresnel's
diffraction:
The
diffraction which is obtained due to the source slits and screen at a finite
distance is called fresnel’s diffraction. In this diffraction, the wave front
is spherical. So, diffraction pattern obtained on the screen are quite complex.
2.Fraunhoffer’s
diffraction:
The
diffraction which is obtained due to the source slits and screen at infinite
distance is called fraunhoffer’s diffraction. In this diffraction, the wave
front is plane. So, diffraction pattern obtained on the screen are simple. In
this diffraction lenses are used to converge the ray of light on screen or
slits.
Fraunhoffers’s
single slits diffraction:
Figure shows
experimental arrangement of fraunhoffers single slits diffraction. It consists
of two lenses $'L_1'$, and $'L_2'$ for the converging of ray of light on slit and
screen from the source ‘S’.
All parallel
rays of light focus at the center of screen. So, center of screen is bright
called center maxima.
On the
screen, diffraction pattern i.e., bright and dark fringes is obtained due to
superimpose of diffracted rays which are called secondary maxima and minima.
Draw ‘AN’
perpendicular on ‘BP’ the ‘BN’ gives path difference between ‘AP’ and ‘BP’
rays.
Therefore,
path difference(x)=BN
In triangle ABN,
$\sin\theta=\frac{BN}{AB}=\frac{BN}{a}$ where a$\to$width of slits
$BN=a\sin\theta$
Therefore, path
difference$(x)=a\sin\theta$….(i)
For secondary maxima,
Path difference$(x)=\frac{(2n+1)\lambda}{2}$ where n=0,1,2
$a\sin\theta=\frac{(2n+1)\lambda}{2}$
$a\sin\theta=\frac{(2n+1)\lambda}{2a}$
for small $'\theta'$, $\sin\theta\approx\theta$
$\therefore \theta_{n}=\frac{(2n+1)\lambda}{2a}$
This is the angular
width of nth secondary maxima.
For n=1, $\theta_1=\frac{3\lambda}{2a}$ $\rightarrow$1st
secondary maxima
For n=2, $\theta_2=\frac{5\lambda}{2a}$ $\rightarrow$ 2nd secondary maxima and so on.
If ‘y’ be linear width of nth fringe and ‘D’ be distance between slit and screen. Then,
$\theta=\frac{y_n}{D}$
$y_n=\theta_n D$
For secondary minima,
Path difference$(x)=n\lambda$
$a\sin\theta=n\lambda$
$\sin\theta=\frac{n\lambda}{a}$
for small $\theta$, $\sin\theta\approx\theta$
$\theta_n=\frac{n\lambda}{a}$ Angular width of nth
secondary minima
and,
$y_n=\theta_n D$
$y_n=\frac{n\lambda D}{a}$
$y_n=\frac{n\lambda D}{a}$ Linear width of nth
secondary minima
Width
of central maxima:
The
width of central maxima is twice of 1st secondary minima
Width of central maxima=$2y=\frac{2\lambda{D}}{a}$
Angular width of central maxima=$2\theta_1=\frac{2\lambda}{a}$
Diffraction grating:
An arrangement of large number of parallel slits is called diffraction
grating. The diffraction grating can be obtained by ruling lines over the glass
surface.
When the lines are ruling over transparent glass surface then the
grating is called transmission grating.
And, when lines are ruling over reflecting glass surface then the
grating is called reflecting grating.
Let us consider 'N' identical slits of width ‘a’ separated by identical
opaque of width ‘b’ in l inch glass then,
$Na+Nb = 1 inch$
$N(a+b) = 1$
$\Rightarrow a+b=\frac{1}{N}$
Here, $(a+b)$ is called grating element. Hence, grating element is
defined as the sum of width of each slit and each opaque.
Path difference between rays is;
$x=(a+b)\sin\theta$
for maxima,
$(a+b)\sin\theta=n$
$d\sin\theta=n\lambda$ where $d=a+b$
The ability of an optical instrument to produce
separate images of two objects very close together is called resolving power.
Rayleigh Criterion: When the central maximum in the diffraction pattern of one point source falls over the other point source, then the two points sources are said to have been resolved by optical instrument.
Resolving power of a Microscope:
The resolving power of a microscope is defined as
the reciprocal of the distance between two objects which can be just resolved
when seen through the microscope.
Resolving power=$\frac{1}{\delta d}=\frac{2\mu \sin(\theta)}{\lambda}$
Resolving power depends on;
(i)wavelength, $\lambda$
(ii)refractive index of the medium between the
object and the objective, and
(iii)half angle of the cone of light from one of
the objects $\theta$.
Resolving power of a Telescope:
The resolving power of a telescope is defined as
the reciprocal of the smallest angular separation between two distant objects
whose images are seen separately.
Resolving power= $\frac{1}{d\theta}=\frac{a}{1.22 \lambda}$
Resolving power depends on;
(i)wavelength $\lambda$
(ii)diameter of the objective, a